11x^2-22x-33=0

Solution for 11x^2-22x-33=0 equation:

11x^2-22x-33=0

a = 11; b = -22; c = -33;
Δ = b2-4ac
Δ = -222-4·11·(-33)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-44}{2*11}=\frac{-22}{22}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+44}{2*11}=\frac{66}{22}
=3
$